Correct answer is : B

We are passing 2 positional arguments, so 1 will be assigned to a, and 2 will be assigned to b
As there is a default value for c already in function definition, it will print 5 although we are not providing it in function call

Correct answer is : D

The arguments will be assigned as follows
x => 1 # positional argument
y => 3 # keyword argument
z => 2 # overriding keyword argument

Correct answer is : C

1 is a positional argument, so will be assigned to x
2, 3 are arbitrary arguments will be assigned to args tuple

Correct answer is : C

The 1 matches x by position,
5 and 6 match y and z by *name positional (6 overrides z’s default),
k defaults to 4 because it was not passed a value.

Correct answer is : B

The arguments in python passed as reference,
Here list is passed as reference. So changing an inner object will change the list

Correct answer is : B

Here p = ['pass', 'except']we are reassigning a new list to "p" so new object is created
So id() value will be changed

Correct answer is : A

foo = lambda a, b: a if a < b else b is similar to

def foo(a, b):
    if a < b:
        return a
    else:
        return b

Correct answer is : A

global y will make the variable "y" to become global inside the function block and x remains local to the function
So any change to "y" will reflect in global scope and y becomes 56 after function call
The output will be 10 56

Correct answer is : C

The function without a return statement returns a None value.

Correct answer is : A

In foo(7)we are passing the value for "a" only, so a becomes 7 and b value will be same as value of "x" i.e. 27
So it will print 7 27

Correct answer is : B

The global variable "x" value will be changed to 4 when foo() is called
Inside function bar() , the global variable "x" value will be 4 and getting added to 7 and 8 in statement a + b + x, when bar() is called

Correct answer is : B

"a" and "b" are global variables are defined outside function (at module namespace)
"c" is explicitly defined as global inside the function in this statement global c and assigning value 1 + 2 = 3 to in this statement c = a + b
So all the variables a, b and c are global and will be printed as 1 2 3

Correct answer is : A

If you already have a global variable with the same name and you again define a new variable with same name, due to the precedence global variable will be overridden

x = "python"
def foo():
    x = "cpyhon"
    print(x)
foo()

It prints "cpyhon"

Correct answer is : B

Recursive function is a function that calls itself

Correct answer is : C

Here foo() function calls it self until y value becomes zero
On every call it doe a floor division foo(y//2) and call it self