Correct answer is : D

// is a floor division operator which truncates the remainder i.e. 0.25 in this case

Correct answer is : B

"/" has higher precedence than "+". So 76.66+9/4 will be evaluated as 76.66 + 2.25results in 78.91
int(78.91) will convert 78.91 to integer type

Correct answer is : D

int(6.77)will be explicitly converted to 6 and the expression will be evaluated as float(6 + 6 % 5)
"%" has higher precedence than "+" so 6 % 5 will be evaluated first results in 1 and then added to 6 becomes 7
Then 7 will be explicitly converted to float type using float() results in 7.0 finally

Correct answer is : B

In explicit conversion user has to use methods like float(), int(), str() to convert one data type to another.
In this case python does not converts the type automatically
For example:

>>> "123" + 456
Traceback (most recent call last):
File "", line 1, in
TypeError: must be str, not int
>>>

Here python cannot convert 456 to str type automatically
We need to str() for this:

>>> "123" + str(456)
'123456'
>>>

Correct answer is : C

in case of 7.0 + 5 , python automatically converts integer type 5 to float type 5.0 which is know as implicit conversion

Correct answer is : C

int(x, base=10) - Return an integer object constructed from a number or string x, or return 0 if no arguments are given
The default base is 10. The allowed values are 0 and 2–36
Base 0 means to interpret exactly as a code literal, so that the actual base is 2, 8, 10, or 16, and so that int('010', 0) is not legal, whileint('010')is, as well asint('010', 8).

Correct answer is : B

int() can't convert non-string with explicit base.
We need to provide the first argument to int() as string if base is passed to it.
Correct syntax:

int('101010', 2)
int(101010) # base value not provided . So no error

Correct answer is : D

bin(20) will be converted to 0b110010 and bin(30) to 0b11110
Concatenating both gives 0b101000b11110 on console

Correct answer is : D

& is bitwise AND operator.

The binary form of  13 is '1101' and 14 is '1110' .

So bit wise AND will give '1100' which is nothing but 12

Correct answer is : D

| is bit wise OR operator.

Binary form of 0x23 is 100011 and of 0x45 is 1000101.

Bit wise OR to will give us 1100111 which is 103