Correct answer is : A
In the expression s2 = s1[:] , a shallow copy of s1 is assigned to s2.
In case of shallow copy the reference to the inner elements like [82, 75] will be same.
So any change to [82, 75] in the new list s2 will change the inner list [82, 75] and s2[2][1] = 23 will make it [82, 23]
Comment here: